How To Find The Highest Salary In SQL Server using MAX, DENSE_RANK, and SUB QUERY?

Method 1  SQL:-

SQL Server 2nd, 3rd, 4th... Highest salary using MAX,  DENSE_RANK, and SUB QUERY!

We can find the 2^nd, 3^rd, 4^th ... n^th highest salary using SQL Server the below query, In the below query use top 1 for the 2^nd highest salary, top 2 for the 3^rd highest salary, top 3 for the 4^th highest salary,.... n^th for the (n+1) highest salary.

Method 2 for MySQL:-

You can use LIMIT to get 2^nd, 3^rd, 4^th ... n^th highest salary!

Examples using MAX,  DENSE_RANK in SQL

====================================

DECLARE @Employees TABLE (

  employee_id INT,

  name VARCHAR(25),

  salary INT

)

INSERT INTO @Employees (employee_id, name, salary)

VALUES 

(1, 'Anil', 62000),

(2, 'Alok', 55000),

(3, 'Ajay', 70000),

(4, 'Rahul', 62000),

(5, 'Diya', 75000);

SELECT 

SALARY,

    DENSE_RANK() OVER (ORDER BY SALARY DESC) AS SALARY_RANK

FROM @Employees

/*Example 1  with Max*/

============================================

SELECT MAX(salary) AS SecondHighestSalary

FROM @Employees

WHERE salary < (SELECT MAX(salary) FROM @Employees);

/*Example 2 with  DENSE_RANK*/

================================================

;with cte as (

select salary, dense_rank() over( order by salary desc) as SalaryRank

from @Employees

)

select * from cte where SalaryRank=2 -- 2 = 2nd Highest Salary, 3 = 3rd Highest Salary, n = nth Highest Salary

================================================

The examples using SUB QUERY,

--QUERY FOR THE 2ND HIGHEST SALARY
SELECT MAX(salary) AS [2ndHighestSalary]
      FROM Employee  WHERE salary not in (SELECT TOP 1 salary  FROM Employee
 GROUP BY salary ORDER BY salary DESC)

--QUERY FOR THE 3RD HIGHEST SALARY 
SELECT MAX(salary) AS [3rdHighestSalary]
      FROM Employee  WHERE salary  not in (SELECT TOP 2 salary  FROM Employee
GROUP BY salary ORDER BY salary DESC)

--QUERY FOR THE 4TH HIGHEST SALARY 
SELECT MAX(salary) AS [4thHighestSalary]
      FROM Employee  WHERE salary   not in (SELECT TOP 3 salary  FROM Employee
GROUP BY salary ORDER BY salary DESC)

--QUERY FOR THE 5TH HIGHEST SALARY 
SELECT MAX(salary) AS [5thHighestSalary]
      FROM Employee  WHERE salary   not in (SELECT TOP 4 salary  FROM Employee
GROUP BY salary ORDER BY salary DESC)

--QUERY FOR THE NTH HIGHEST SALARY 
SELECT MAX(salary) AS [nthHighestSalary]
      FROM Employee  WHERE salary   not in (SELECT TOP (n-1) salary  FROM Employee
GROUP BY salary ORDER BY salary DESC)

In MySQL simple and sweeter 2nd, 3rd, 4th... Highest salary.

You can use LIMIT to get highest salary!

Examples using MySQL LIMIT,

--QUERY FOR THE 2ND HIGHEST SALARY USINGH LIMIT
SELECT salary FROM Employee ORDER BY salary DESC LIMIT 1, 1;

--QUERY FOR THE 3rd HIGHEST SALARY USINGH LIMIT
SELECT salary FROM Employee ORDER BY salary DESC LIMIT 2, 1;

--QUERY FOR THE 4th HIGHEST SALARY USINGH LIMIT
SELECT salary FROM Employee ORDER BY salary DESC LIMIT 3, 1;

I hope you are enjoying with this post! Please share with you friends. Thank you!